Odpowiedź :
Dane:
m - masa = 200 t = 200000 kg
h = 10km = 10000m
v = 1080 km/h = 300 m/s
[tex]E_ p =energia~potencjalna=m*g*h=200000kg*9,81\frac{m}{s^2}*10000m=1,962*10^{10}J[/tex]
[tex]E_k = energia~kinetyczna=\frac{mv^2}{2} = \frac{200000kg*(300\frac{m}{s})^2 }{2} = 9*10^9 J[/tex]
[tex]dane:\\m = 200 \ t = 200 \ 000 \ kg = 2\cdot10^{5} \ kg\\h = 10 \ km = 10 \ 000 \ m = 10^{4} \ m\\v = 1080\frac{km}{h} = 1089\cdot\frac{1000 \ m}{3600 \ s} = 300\frac{m}{s} = 3\cdot10^{2\frac{m}{s}}\\g = 10\frac{N}{kg}}\\szukane:\\E_{p} = ?\\E_{k} = ?\\\\Rozwiazanie\\\\E_{p} = mgh\\\\E_{p} = 2\cdot10^{5} \ kg\cdot10\frac{N}{kg}\cdot10^{4}\frac{m}{s} = 20\cdot10^{9} \ J = 20 \ GJ\\\\\\[/tex]
[tex]E_{k} = \frac{1}{2}mv^{2}\\\\E_{k} = \frac{1}{2}\cdot2\cdot10^{5} \ kg\cdot(3\cdot10^{2}\frac{m}{s})^{2}=9\cdot10^{9} \ J = 9 \ GJ\\\\1 \ kJ = 1000 \ J = 10^{3} \ J\\1 \ MJ = 1 \ 000 \ 000 \ J = 10^{6} \ J\\1 \ GJ = 1 \ 000 \ 000 \ 000 \ J = 10^{9} \ J[/tex]