Yoloneaa
Rozwiązane

Bardzo pilne !!! Potrzebne na już !

9/142
Przykłady e,f,g,h



Bardzo Pilne Potrzebne Na Już 9142 Przykłady Efgh class=

Odpowiedź :

Tojamiki

Odpowiedź:

e)

1/2(y + 3/4) + 1/4(2y - 1/2) = y + 1/4

1/2y + 3/8 + 1/2y - 1/8 = y + 1/4

y + 2/8 = y + 1/4

y - y = 1/4 - 1/4

0 = 0

rownanie tozsamosciowe

rozwiazaniem sa wszystkie liczby rzeczywiste

f)

1/5( y - 3) - 2/3(y - 3/5) + 1/3 = 2/5 - 1/3(2y - 3)

1/5y - 3/5 - 2/3y + 2/5 + 1/3 = 2/5 - 2/3y + 1

1/5y - 2/3y + 2/3y = 1 2/5 + 1/5

1/5y = 1 3/5         /*5

y = 5 * 8/5 = 8

g)

(y - 2)/3 + 1/15 - (2y - 5)/3 = (8 - 4y)/5

1/3y  - 2/3 + 1/15 - 2/3y + 5/3 = 8/5 - 4/5y

-1/3y + 4/5y = 8/5 - 1/15 - 1

-5/15y + 12/15y = 1 3/5 - 1/15 - 1

7/15y = 3/5 - 1/15       /*15/7

y = 15/7(9/15 - 1/15) = 15/7 * 8/15 = 8/7 = 1 1/7

h)

(y - 5)/2 + (2y + 3)/5 + 1/3 = (y + 7)/15 + y/2

1/2y - 5/2 + 2/5y + 3/5 + 1/3 = 1/15y + 7/15 + 1/2y

1/2y + 2/5y - 1/15y - 1/2y = 7/15 + 2 1/2 - 3/5 - 1/3

6/15y - 1/15y = 7/15 - 9/15 + 2 3/6 - 2/6

5/15y = -2/15 + 2 1/6

1/3y = -4/30 + 2 5/30     /*3

y = 2 1/30 * 3 = 61/30 * 3 = 61/10 = 6,1

Szczegółowe wyjaśnienie:

Magda

Odpowiedź:

[tex]e)\\\\\frac{1}{2}(y+\frac{3}{4})+\frac{1}{4}(2y-\frac{1}{2})=y+\frac{1}{4}\\\\\frac{1}{2}y+\frac{3}{8}+\frac{1}{2}y-\frac{1}{8}=y+\frac{1}{4}\\\\y+\frac{2}{8}=y+\frac{1}{4}\\\\y+\frac{1}{4}=y+\frac{1}{4}\\\\y-y=\frac{1}{4}-\frac{1}{4}\\\\0=0\\\\R\'ownanie\ \ to\.zsamo\'sciowe\ \ ma\ \ niesko\'nczenie\ \ wiele\ \ rozwiaza\'n[/tex]

[tex]f)\\\\\frac{1}{5}(y-3)-\frac{2}{3}(y-\frac{3}{5})+\frac{1}{3}=\frac{2}{5}-\frac{1}{3}(2y-3)\\\\\frac{1}{5}y-\frac{3}{5}-\frac{2}{3}y+\frac{2}{5}+\frac{1}{3}=\frac{2}{5}-\frac{2}{3}y+1\\\\\frac{1}{5}y-\frac{1}{5}-\frac{2}{3}y+\frac{1}{3}=\frac{7}{5}-\frac{2}{3}y\ \ /\cdot15\\\\3y-3-10y+5=21-10y\\\\-7y+2=21-10y\\\\-7y+10y=21-2\\\\3y=19\ \ /:3\\\\y=\frac{19}{3}\\\\y=6\frac{1}{3}[/tex]

[tex]g)\\\\\frac{y-2}{3}+\frac{1}{15}-\frac{2y-5}{3}=\frac{8-4y}{5}\ \ /\cdot15\\\\5(y-2)+1-5(2y-5)=3(8-4y)\\\\5y-10+1-10y+25=24-12y\\\\-5y+16=24-12y\\\\-5y+12y=24-16\\\\7y=8\ \ /:7\\\\y=\frac{8}{7}\\\\y=1\frac{1}{7}[/tex]

[tex]h)\\\\\frac{y-5}{2}+\frac{2y+3}{5}+\frac{1}{3}=\frac{y+7}{15}+\frac{y}{2}\ \ /\cdot30\\\\15(y-5)+6(2y+3)+10=2(y+7)+15y\\\\15y-75+12y+18+10=2y+14+15y\\\\27y-47=17y+14\\\\27y-17y=14+47\\\\10y=61\ \ /:10\\\\y=\frac{61}{10}\\\\y=6\frac{1}{10}[/tex]

Inne Pytanie