Odpowiedź:
[tex]\dfrac{sin60^{\circ}+2cos150^{\circ}-sin120^{\circ}}{3tg150^{\circ}}=\dfrac{\frac{\sqrt{3}}{2}+2\cdot(-\frac{\sqrt{3}}{2})-\frac{\sqrt{3}}{2}}{3\cdot(-\frac{\sqrt{3}}{3})}=\dfrac{\not2\cdot(-\frac{\sqrt{3}}{\not2})}{\not3\cdot(-\frac{\sqrt{3}}{\not3})}=\\\\=\dfrac{-\sqrt{3}}{-\sqrt{3}}=1[/tex]
