Proszę pomóżcie daje naj
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[tex]3 = \sqrt{9} \: wiec \: 3 \sqrt{6} = \sqrt{9 } \times \sqrt{6} = \sqrt{9 \times 6} = \sqrt{54} [/tex]
[tex]2 = \sqrt{4} \: wiec \: 2 \sqrt{5} = \sqrt{4} \times \sqrt{5} = \sqrt{4 \times 5} = \sqrt{20} [/tex]
[tex]5 = \sqrt{25} \: wiec \: 5 \sqrt{2} = \sqrt{25} \times \sqrt{2} = \sqrt{25 \times 2} = \sqrt{50} [/tex]
[tex]2 = \sqrt{4} \: wiec \: 2 \sqrt{2} = \sqrt{4} \times \sqrt{2} = \sqrt{4 \times 2} = \sqrt{8} [/tex]
[tex]3 = \sqrt{9} \: wiec \: 3 \sqrt{2} = \sqrt{9} \times \sqrt{2} = \sqrt{9 \times 2} = \sqrt{18} [/tex]