Odpowiedź:
[tex]\begin{cases}0,5y=3+2x\\x-2y=2\end{cases}\\\\\\\begin{cases}-2x+0,5y=3\\x-2y=2\ \ /\cdot2\end{cases}\\\\\\+\begin{cases}-2x+0,5y=3\\2x-4y=4\end{cases}\\---------\\-3,5y=7\ \ /:(-3,5)\\y=-2\\\\\\x-2\cdot(-2)=2\\\\x+4=2\\\\x=2-4\\\\x=-2\\\\\\\begin{cases}x=-2\\y=-2\end{cases}[/tex]
