[tex]Zadanie\\\\A.\\\\-14\frac{1}{3}+(-6,5)+11\frac{5}{6}=-14\frac{1}{3}-6\frac{1}{2} +11\frac{5}{6}=-14\frac{2}{6}-6\frac{3}{6} +11\frac{5}{6}=-20\frac{5}{6}+11\frac{5}{6}=-9\\\\B.\\\\ 4,2+(-5\frac{2}{3})+(-2\frac{3}{5})=4\frac{2}{10}-5\frac{2}{3}-2\frac{3}{5}=4\frac{1}{5}- 5\frac{10}{15}-2\frac{9}{15}=4\frac{3}{15}-7\frac{19}{15}=\\\\=-3 \frac{16}{15}=-4\frac{1}{15}[/tex]
[tex]C.\\\\-7\frac{5}{8}+12,75+(-5,5)=-7\frac{5}{8}+ 12\frac{75}{100}-5\frac{5}{10}=-7\frac{5}{8}+12\frac{3}{4}-5\frac{1}{2}=-7\frac{5}{8}+12\frac{6}{8}-5\frac{4}{8}=\\\\=-12\frac{9}{8} +12\frac{6}{8}=-\frac{3}{8}[/tex]
