[tex]\dfrac{\cos \alpha}{1+\sin \alpha}+\dfrac{\cos \alpha}{1+\sin \alpha}=\dfrac{2}{\cos\alpha}\\\\\dfrac{2\cos \alpha}{1+\sin \alpha}=\dfrac{2}{\cos\alpha}\\\\\dfrac{\cos \alpha}{1+\sin \alpha}=\dfrac{1}{\cos\alpha}\\\\\cos^2\alpha=1+\sin\alpha[/tex]
Nie jest.
