[tex]c] \ 6\sqrt{1,5}=\sqrt{6^2\cdot1,5}=\sqrt{36\cdot1,5}=\sqrt{54}\\\\d] \ 1,5\sqrt6=\sqrt{1,5^2\cdot6}=\sqrt{2,25\cdot6}=\sqrt{13,5}\\\\e] \ -3\sqrt[3]2=\sqrt[3]{(-3)^3\cdot2}=\sqrt[3]{(-27)\cdot2}=\sqrt[3]{-54}\\\\f] \ 2\sqrt[3]{-10}=\sqrt[3]{2^3\cdot(-10)}=\sqrt[3]{8\cdot(-10)}=\sqrt[3]{-80}\\\\g] \ 4\sqrt[3]5=\sqrt[3]{4^3\cdot5}=\sqrt[3]{64\cdot5}=\sqrt[3]{320}\\\\h] \ 5\sqrt[3]{-2}=\sqrt[3]{5^3\cdot(-2)}=\sqrt[3]{125\cdot(-2)}=\sqrt[3]{-250}[/tex]
