Odpowiedź:
[tex]3\cdot\frac{7}{2}+2\frac{1}{4}=\frac{21}{2}+2\frac{1}{4}=10\frac{1}{2}+2\frac{1}{4}=10\frac{2}{4}+2\frac{1}{4}=12\frac{3}{4}\\\\\\3\frac{1}{2}\cdot2\frac{1}{4}=\frac{7}{2}\cdot\frac{9}{4}=\frac{63}{8}=7\frac{7}{8}\\\\\\3\frac{1}{3}-2\frac{1}{4}=3\frac{4}{12}-2\frac{3}{12}=1\frac{1}{12}\\\\\\3\frac{1}{2}:2\frac{1}{4}=\frac{7}{2}:\frac{9}{4}=\frac{7}{\not2_{1}}\cdot\frac{\not4^2}{9}=\frac{14}{9}=1\frac{5}{9}[/tex]
[tex]\frac{1}{2}:9\frac{2}{3}=\frac{1}{2}:\frac{29}{3}=\frac{1}{2}\cdot\frac{3}{29}=\frac{3}{58}\\\\\\5\frac{2}{5}+\frac{5}{6}=5\frac{12}{30}+\frac{25}{30}=5\frac{37}{30}=6\frac{7}{30}\\\\\\1\frac{2}{10}:2\frac{3}{5}=1\frac{1}{5}:\frac{13}{5}=\frac{6}{\not5_{1} }\cdot\frac{\not5^1}{13}=\frac{6}{13}[/tex]
