Odpowiedź:
[tex]Zad.1\\\\a)\ \ 27^3:9^4=(3^3)^3:(3^2)^4=3^{9}:3^8=3^{9-8}=3^1\\\\b)\ \ 70^5:35^5=(70:35)^5=2^5\\\\c)\ \ (8^4)^2\cdot64^2=8^8\cdot(8^2)^2=8^8\cdot8^4=8^{8+4}=8^{12}\\\\\\Zad.2\\\\(\frac{5}{9}+0,6):2=(\frac{5}{9}+\frac{3}{5}):2=(\frac{25}{45}+\frac{27}{45}):2=\frac{\not52^2^6}{45}\cdot\frac{1}{\not2_{1}}=\frac{26}{45}[/tex]
