Zadanie
1 m = 10 dm
1 m³ = 1000 dm³
V = 0,125 m³ = 125 dm
V = a³
a³ = ∛125
a = 5 dm
Pc = 6 · a²
Pc = 6 · 5² = 6 · 25 = 150 dm²
[tex]V = 0,125 \ m^{3}\\oraz\\V = a^{3}\\\\a^{3} = 0,125 \ m^{3}\\\\a = \sqrt[3]{0,125}\\\\a = 0,5 \ m\\\\P_{c} = 6a^{2} = 6\cdot0,5^{2} = 6\cdot0,25 = 1,5 \ m^{2}\\\\Suma \ krawedzi:\\12\cdot0,5 = 6 \ m[/tex]
