Odpowiedź:
Zad.1
[tex]a) \frac{4}{9} + \frac{1}{9} = \frac{5}{9}[/tex]
[tex]b)\frac{6}{7} +\frac{4}{7} = \frac{10}{7} = 1\frac{3}{7}[/tex]
[tex]c) 3\frac{2}{9} + \frac{4}{9} = 3 \frac{6}{9} = 3 \frac{2}{3}[/tex]
[tex]d) 2 \frac{5}{7} + 3 \frac{6}{7} = 5\frac{11}{7} = 6\frac{4}{7}[/tex]
[tex]e)\frac{12}{13} - \frac{5}{13} = \frac{7}{13}[/tex]
[tex]f)3 \frac{16}{23} - 1 \frac{9}{23} = 2 \frac{7}{23}[/tex]
[tex]g) 8 - \frac{6}{7} = 7 \frac{1}{7}[/tex]
[tex]h)4\frac{3}{6} - 1 \frac{5}{6} = 3 \frac{9}{6} - 1 \frac{5}{6} = 2 \frac{4}{6} = 2 \frac{4}{6}[/tex]
Zad.2
[tex](4\frac{9}{10} + 2\frac{3}{10}) - (6\frac{3}{10} - 2 \frac{7}{10} ) = 6 \frac{12}{10} - (6\frac{3}{10} - 2 \frac{7}{10} ) = 6 \frac{12}{10} - (5 \frac{13}{10} - 2 \frac{7}{10} ) = 6 \frac{12}{10} - 3\frac{6}{10} = 3\frac{6}{10} = 3 \frac{3}{5}[/tex]
Szczegółowe wyjaśnienie:
Mam nadzieję że pomogłam :)
