Hej!
[tex]x^2+2x-3=0\\\\a=1, \ b=2, \ c=-3\\\\\Delta=b^2-4ac\rightarrow2^2-4\cdot1\cdot(-3)=4+12=16\\\\\sqrt{\Delta}=\sqrt{16}=4\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-2-4}{2\cdot1}=\frac{-6}{2}=\boxed{-3}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-2+4}{2\cdot1}=\frac{2}{2}=\boxed1[/tex]