[tex]dane:\\m = 45 \ kg\\E_{p} = 0,34 \ kJ = 0,34\cdot1000 \ J = 340 \ J\\g = 10\frac{N}{kg}\\szukane:\\h = ?\\\\E_{p} = mgh \ \ /:mg\\\\h = \frac{E_{p}}{mg}\\\\h = \frac{340 \ J}{45 \ kg\cdot10\frac{N}{kg}} = \frac{340 \ N\cdot m}{450 \ N}=0,7(5) \ m\approx0,76 \ m[/tex]
