[tex]0,8 + \frac{0,3}{41}\cdot100\% = \frac{8}{10}+\frac{\frac{3}{10}}{41}}\cdot1 = \frac{4}{5}+\frac{3}{410} =\frac{328}{410} + \frac{3}{410} = \frac{331}{410}[/tex]
[tex]1,8+\frac{0,3}{59,6}\cdot100\% = \frac{18}{10}+\frac{3}{596}\cdot1 = \frac{9}{5}+\frac{3}{596} = \frac{5364}{2980} + \frac{15}{2980} = \frac{5379}{2980} = 1\frac{2399}{2980}[/tex]