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Obliczenia
[tex] \frac{ \sqrt{27} }{ \sqrt{48} - \sqrt{12} } = \frac{ \sqrt{9 \times 3} }{ \sqrt{16 \times 3} - \sqrt{4 \times 3} } = \frac{ \sqrt{ {3}^{2} \times 3 } }{ \sqrt{ {4}^{2} \times 3} - \sqrt{ {2}^{2} \times 3} } = \\ \\ = \frac{3 \sqrt{3} }{4 \sqrt{3} - 2 \sqrt{3} } = \frac{3 \sqrt{3} }{2 \sqrt{3} } = \frac{3}{2} = 1 \frac{1}{2} [/tex]
Pozdrawiam! ~ JulkaOdMatmy