Cześć!
[tex]log_b \sqrt{a} = 0,125 \iff b^{\frac{1}{8}}=\sqrt{a} \iff b^{\frac{1}{8}}= a^{\frac{1}{2}} \iff (b^{\frac{1}{8}})^8 = (a^{\frac{1}{2}})^8 \iff\\\\\iff b=a^4[/tex]
Wówczas:
[tex]log_a b = x \iff a^x = b \iff a^x=a^4 \iff x=4[/tex]
Pozdrawiam!
