Cześć ;-)
Obliczenia od a] do c]
[tex]a] \ \sqrt{0,81}=\sqrt{\frac{81}{100}}=\frac{\sqrt{81}}{\sqrt{100}}=\frac{\sqrt{9^2}}{\sqrt{10^2}}=\frac{9}{10}\\\\b] \ \sqrt{1,96}=\sqrt{1\frac{96}{100}}=\sqrt{1\frac{24}{25}}=\sqrt{\frac{49}{25}}=\frac{\sqrt{49}}{\sqrt{25}}=\frac{\sqrt{7^2}}{\sqrt{5^2}}=\frac{7}{5}=1\frac{2}{5}\\\\c] \ \sqrt{\frac{16}{169}}=\frac{\sqrt{16}}{\sqrt{169}}=\frac{\sqrt{4^2}}{\sqrt{13^2}}=\frac{4}{13}\\\\[/tex]
Obliczenia od d] do e]
[tex]d] \ \sqrt{\frac{50}{162}}=\sqrt{\frac{25}{81}}=\frac{\sqrt{25}}{\sqrt{81}}=\frac{\sqrt{5^2}}{\sqrt{9^2}}=\frac{5}{9}\\\\e] \ \sqrt{2\frac{2}{49}}=\sqrt{\frac{100}{49}}=\frac{\sqrt{100}}{\sqrt{49}}=\frac{\sqrt{10^2}}{\sqrt{7^2}}=\frac{10}{7}=1\frac{3}{7}[/tex]
Pozdrawiam! ~ JulkaOdMatmy
Odpowiedź:
a)
[tex] \sqrt{0.81} = 0.9[/tex]
b)
[tex] \sqrt{1.96} = 1.4[/tex]
c)
[tex] \sqrt{ (\frac{16}{169} )} = \frac{ \sqrt{16} }{ \sqrt{169} } = \frac{4}{13} [/tex]
d)
[tex] \sqrt{ \frac{50}{162} } = \sqrt{ \frac{25}{81} } = \frac{ \sqrt{25} }{ \sqrt{81} } = \frac{5}{9} [/tex]
e)
[tex] \sqrt{2 \frac{2}{49} } = \sqrt{ \frac{2 \times 49 + 2}{49} } = \sqrt{ \frac{100}{49} } = \frac{ \sqrt{100} }{ \sqrt{49} } = \frac{10}{7} [/tex]