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[tex]1\frac{2}{5}-3\frac{7}{8}-0,125=1\frac{2}{5}-(3\frac{7}{8}+\frac{125}{1000})=\\\\=1\frac{2}{5}-(3\frac{7}{8}+\frac{1}{8})=1\frac{2}{5}-4=-(4-1\frac{2}{5})=\boxed{-2\frac{3}{5}}[/tex]
Pozdrawiam! ~ JulkaOdMatmy
[tex]1\frac{2}{5} -3\frac{7}{8} -0,125=1\frac{2}{5} -3\frac{7}{8}-\frac{1}{8} =1 \frac{16}{40} -3\frac{35}{40} -\frac{5}{40} =[/tex]
[tex]=-2\frac{19}{40} -\frac{5}{40} =-2\frac{3}{5}[/tex]