[tex]a)\\\\A= \frac{2}{3} + 4\frac{1}{2}:2\frac{1}{4}=\frac{2}{3} + \frac{9}{2}: \frac{9}{4}=\frac{2}{3} + \frac{\not{9}^1}{\not{2}^1}* \frac{\not{4}^2}{\not{9}^1}=\frac{2}{3}+2=2\frac{2}{3}\\\\B= (\frac{2}{3} + 4\frac{1}{2}):2\frac{1}{4}= (\frac{4}{6} + 4\frac{3}{6}): \frac{9}{4}=4\frac{7}{6}:1\frac{1}{4}=\frac{31}{\not{6}^3}*\frac{\not{4}^2}{9}=\frac{62}{27}=2\frac{8}{27}\\\\\\b)\\\\A= 1\frac{3}{4}*\frac{5}{7}+\frac{5}{8}= \frac{\not{7}^1}{4}*\frac{5}{\not{7}^1}+\frac{5}{8}= \frac{5}{4}+\frac{5}{8}=\frac{10}{8}+\frac{5}{8}=\frac{15}{8}=1\frac{7}{8}\\\\ B= 1\frac{3}{4}*(\frac{5}{7}+\frac{5}{8})= \frac{7}{4}*(\frac{40}{56}+\frac{35}{56})=\frac{\not{7}^1}{4}*\frac{75}{\not{56}^8}=\frac{75}{32}=2\frac{11}{32}[/tex]
[tex]\\\\\\c)\\\\A= 6 - 4 \frac{1}{3}*\frac{12}{3} =6 - \frac{13}{3}*4 =6-\frac{52}{3}=6-17\frac{1}{3}= -11\frac{1}{3}\\\\B=( 6 - 4 \frac{1}{3})*\frac{12}{3} =1\frac{2}{3} *4=\frac{5}{3}*4=\frac{20}{3}=6\frac{2}{3} \\\\\\d)\\\\A= 3\frac{1}{3} *\frac{3}{5} - 1\frac{1}{6}= \frac{\not{10}^2}{\not{3}^1} *\frac{\not{3}^1}{\not{5}^1 } - 1\frac{1}{6} =2-1\frac{1}{6}=1\frac{6}{6}-1\frac{1}{6}=\frac{5}{6}\\\\B= 3\frac{1}{3} *(\frac{3}{5} - 1\frac{1}{6})= 3\frac{1}{3} *(\frac{18}{30} - 1\frac{5}{30})= 3\frac{1}{3} *(\frac{18}{30} - \frac{35}{30})=\frac{\not{10}^1}{3}*(-\frac{17}{\not{30}^3})=\\\\=-\frac{17}{9}=-1\frac{8}{9}[/tex]
