Odpowiedź :
[tex]x^{3} -10x^{2}+ 25x= 0 \\x( x^{2} - 10x+ 25) = 0\\x= 0 i x^{2} -10x+ 25 = 0 \\(x-5)^{2} = 0\\x-5 = 0 \\x= 5[/tex]
[tex]x^{3}-10x^{2}+25x = 0\\\\x(x^{2}-10x+25) = 0\\\\x(x-5)^{2} = 0\\\\x = 0 \ \vee \ x-5 = 0\\\\x = 0 \ \vee \ x = 5\\\\x \in \{0, 5\}[/tex]