[tex]j) \ \frac{5}{6}-\frac{1}{4} = \frac{5\cdot2}{6\cdot2} - \frac{1\cdot3}{4\cdot3} = \frac{10}{12} - \frac{3}{12} = \frac{7}{12}\\\\\\k) \ 1\frac{1}{6}-\frac{7}{9} = 1\frac{1\cdot3}{6\cdot3} -\frac{7\cdot2}{9\cdot2} = 1\frac{3}{18}-\frac{14}{18} = \frac{18+3}{18}-\frac{14}{18} = \frac{21}{18}-\frac{14}{18} = \frac{7}{18}[/tex]
[tex]l) \ 2\frac{3}{8}-1\frac{5}{6} = 2\frac{3\cdot3}{8\cdot3} -1\frac{5\cdot4}{6\cdot4} = 2\frac{9}{24}-1\frac{20}{24} = 1\frac{24+9}{24}-1\frac{20}{24} = 1\frac{33}{24}-1\frac{20}{24} = \frac{13}{24}[/tex]
