Cześć ;-)
e)
[tex]\frac{x+6}{x-2}=\frac{x-2}{x+2}\\\\x-2\neq0\longrightarrow x\neq2\\\\x+2\neq0\longrightarrow x\neq-2\\\\\mathbb{D}:\mathbb{R}-\{-2;2\}\\\\(x+6)(x+2)=(x-2)(x-2)\\\\x^2+2x+6x+12=x^2-2x-2x+4\\\\x^2+8x+12=x^2-4x+4\\\\x^2+8x-x^2+4x=4-12\\\\12x=-8 \ \ /:12\\\\x=-\frac{2}{3}\in\mathbb{D}[/tex]
f)
[tex]\frac{-2x-1}{6x-5}=\frac{x-1}{11-3x}\\\\6x-5\neq0\longrightarrow6x\neq5\longrightarrow x\neq\frac{5}{6}\\\\11-3x\neq0\longrightarrow-3x\neq-11\longrightarrow x\neq\frac{11}{3}\\\\\mathbb{D}:\mathbb{R}-\{\frac{11}{3};\frac{5}{6}\}\\\\(6x-5)(x-1)=(-2x-1)(11-3x)\\\\6x^2-6x-5x+5=-22x+6x^2-11+3x\\\\6x^2-11x+5=6x^2-19x-11\\\\6x^2-11x-6x^2+19x=-11-5\\\\8x=-16 \ \ /:8\\\\x=-2\in\mathbb{D}[/tex]
Pozdrawiam!