zad. 16
[tex]a)2 \times {2}^{2} \times 8 \div 16 = 2 \times {2}^{2} \times {2}^{3} \div {2}^{4} = {2}^{6} \div {2}^{4} = {2}^{2} = 4[/tex]
[tex]b)( - 3 {)}^{2} \times ( - 27) \times ( - 3 {)}^{5} \div {3}^{7} = ( - 3 {)}^{2} \times ( - 3 {)}^{3} \times ( - 3 {)}^{5} \div {3}^{7} = ( - 3 {)}^{10} \div {3}^{7} = {3}^{10} \div {3}^{7} = {3}^{3} = 27[/tex]