ShttyNerd
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3 Przedstaw iloraz potęg w postaci potęgi ilorazu i oblicz.
(-4)² (0,55) 1212
a)
82
(0,11)2' 112
(-4,816 : (-43)
b) (-2,56)) : (15), (-0,92 : (), (13)*: (-27)



3 Przedstaw Iloraz Potęg W Postaci Potęgi Ilorazu I Oblicz 4 055 1212 A 82 0112 112 4816 43 B 256 15 092 13 27 class=

Odpowiedź :

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Zobacz obrazek Dino485

a)

[tex]\frac{(-4)^{2}}{8^{2}} = (\frac{-4}{8})^{2} = (-\frac{1}{2})^{2} = \frac{1}{4}\\\\\\\frac{(0,55)^{2}}{(0,11)^{2}} = (\frac{0,55}{0,11})^{2} = (\frac{55}{11})^{2} = 5^{2} = 25\\\\\\\frac{121^{2}}{11^{2}} = (\frac{121}{11})^{2} = 11^{2} = 121\\\\\\(-4,8)^{6}:(-4\frac{4}{5})^{6} = (-4,8)^{6}:(-4,8)^{6} = (\frac{-4,8}{-4,8})^{6} = 1^{6} = 1[/tex]

b)

[tex](-2,56)^{3}:(\frac{16}{25})^{3}= (-\frac{256}{100})^{3}:(\frac{16}{25})^{3} = (-\frac{256}{100})^{3}:(\frac{16}{25})^{3} =(-\frac{64}{25}:\frac{16}{25})^{3} =\\\\= (-\frac{64}{25}\cdot\frac{25}{16})^{3} = (-4)^{3} = -64[/tex]

[tex](-0,9)^{2}:(\frac{3}{8})^{2} = (-\frac{9}{10}:\frac{3}{2})^{2} = (-\frac{9}{10}\cdot\frac{8}{3})^{2}=(-\frac{12}{5})^{2}} = \frac{144}{25} = 5\frac{19}{25}\\\\\\(1\frac{2}{3})^{4}:(-2\frac{7}{9})^{4} = (\frac{5}{3}:(-\frac{25}{9}))^{4}=(\frac{5}{3}\cdot(-\frac{9}{25}))^{4} = (-\frac{3}{5})^{4} = \frac{81}{625}[/tex]