Odpowiedź:
zad 7
a)[tex](\frac{1}{42} )^3:(-\frac{1}{21} )^3-100*(-\frac{1}{10} )^3=[\frac{1}{42} *(-\frac{21}{1} )} ]^3-[100*(-\frac{1}{10} )]^3=(-\frac{1}{2})^3- (-10)^3=-\frac{1}{8} +1000=999\frac{7}{2}[/tex]
[tex](1,2)^3:12^3-(0,6)^5*(-1\frac{2}{3} )^5=(\frac{12}{10} *\frac{1}{12} )^3-[\frac{6}{10} *(-\frac{5}{3})]^ 5=(\frac{1}{10} )^3-(-1)^5=\frac{1}{1000} +1=1,001[/tex]
[tex]-(-27)^3*(-\frac{1}{9} )^3-12^3:(-3)^3=-[(-27*(-\frac{1}{9} )]^3-[12*(-\frac{1}{3} )]^3=-(3)^3-(-4)^3=-27+64=37[/tex]
d)[tex](-2\frac{2}{3} )^{15}*(0,375)^{15}+(-\frac{2}{3} )^2*(0,75)^2=(-\frac{8}{3} *\frac{3}{8} )^{15}}+(-\frac{2}{3} *\frac{3}{4} )^2=(-1)^{15}+(-\frac{1}{2} )^2=-1+\frac{1}{4} =-\frac{3}{4}[/tex]
Szczegółowe wyjaśnienie:
