Cześć ;-)
Obliczenia
[tex](-\frac{1}{9})^2:(\frac{1}{72})^2-(-\frac{1}{36})^3:(\frac{1}{108})^3=\\\\=(-\frac{1}{9}:\frac{1}{72})^2-(-\frac{1}{36}:\frac{1}{108})^3=(-\frac{1}{9}\cdot72)^2-(-\frac{1}{36}\cdot108)^3=\\\\=(-\frac{72}{9})^2-(-\frac{108}{36})^3=(-8)^2-(-3)^3=64-(-27)=64+27=91\\\\\huge\boxed{\text{Odp}. \ \text{D}}[/tex]
Wykorzystany wzór
[tex]a^m:b^m=(a:b)^m[/tex]
Pozdrawiam!
