Odpowiedź:
Szczegółowe wyjaśnienie:
[tex](-12,8)^0:2^0=1:1=1\neq -1\ \ F\\-2,2+(-1\frac{2}{3})^6*(0,6)^6=-2\frac{1}{5}+(-\frac{5}{3})^6*(\frac{6}{10})^6=-2\frac{1}{5}+(-\frac{5}{3}*\frac{3}{5})^6=-\frac{11}{5}+(-1)^6=-\frac{11}{5}+1=-1 \frac{1}{5} \neq -3\frac{1}{5}\ F\\(\frac{1}{2})^{10}:(0,5)^2*(\frac{3}{6})^3=(\frac{1}{2})^{10}:(\frac{1}{2})^2*(\frac{1}{2})^3=(\frac{1}{2})^5=(\frac{2}{4})^5\ P\\(\frac{-4m}{n})^3:(\frac{2m}{3n})^3=(\frac{-4m}{n}:\frac{2m}{3n})^3=(\frac{-4m}{n}*\frac{3n}{2m})^3=(-6)^3=-216\ P[/tex]
