Witaj :)
[tex]a) \ 2^3=2\cdot 2\cdot 2=8\\\\(\frac{3}{5})^2=\frac{3^2}{5^2} =\frac{3\cdot3}{5\cdot 5} =\frac{9}{25} \\\\(-1)^5=(-1)\cdot (-1)\cdot(-1)\cdot(-1)\cdot (-1)=-1\\\\(-7)^0=1\ wprost\ z\ a^0=1[/tex]
[tex]b)\ (1\frac{2}{5})^2=(\frac{7}{5})^2=\frac{7^2}{5^2}=\frac{7\cdot7}{5\cdot 5} =\frac{49}{50} \\\\(-2\frac{1}{2})^3=(-\frac{5}{3})^3 =-(\frac{5^3}{3^3} )=-(\frac{5\cdot 5\cdot 5}{3\cdot 3\cdot 3})=-\frac{125}{27} =-4\frac{17}{25} \\\\-1,2^2=-(\frac{6}{5})^2=-\frac{6\cdot6}{5\cdot 5} =-\frac{36}{25} =-1\frac{11}{25}\\\\-4^3=-4\cdot 4\cdot 4=-64[/tex]
