[tex]dane:\\v_{o} = 0\\t = 5 \ s\\v = 72\frac{km}{h} = 72\cdot\frac{1000 \ m}{3600 \ s} = 20\frac{m}{s}\\szukane:\\s = ?\\\\Rozwiazanie\\\\s = v_{sr}\cdot t\\\\v_{sr} = \frac{v_{o}+v}{2} = \frac{1}{2}v\\\\s = \frac{1}{2}vt\\\\s = \frac{1}{2}\cdot20\frac{m}{s}\cdot5 \ s\\\\\underline{s = 50 \ m}[/tex]
[tex]Lub:\\\\s = \frac{1}{2}at^{2}\\\\a = \frac{\Delta v}{t} =\frac{v-v_{o}}{t} = \frac{v}{t} = \frac{20\frac{m}{s}}{5 \ s} = 4\frac{m}{s^{2}}\\\\s = \frac{1}{2}\cdot4\frac{m}{s^{2}}\cdot(5 \ s)^{2}\\\\\underline{s = 50 \ m}[/tex]
Odp. Motocyklista pokanał 50 m.
