Odpowiedź :
b)
[tex]4-100x^{2} =0\\4=100x^{2} /:100\\\frac{1}{25} =x^{2} /\sqrt[2]{} \\[/tex]
[tex]x=\frac{1}{5}[/tex] v [tex]x=-\frac{1}{5}[/tex]
c)
[tex]4x^{2} -121=0\\4x^{2} =121/:4\\x^{2} =\frac{121}{4} /\sqrt[2]{} \\[/tex]
[tex]x=\frac{11}{2}[/tex] v [tex]x=-\frac{11}{2}[/tex]
Pozdrawiam.
b)
4-100x²=0 |:4
1-25x²=0
-25x²+1=0
(-5x+1)(5x+1)=0
-5x+1=0 ∨ 5x+1=0
-5x=-1 |:(-5) ∨ 5x=-1
x₁=1/5 ∨ x₂=-1/5
c)
4x²-121=0
(2x-11)(2x+11)=0
2x-11=0 ∨ 2x+11=0
2x=11 |:2 ∨ 2x=-11 |:2
x=11/2 ∨ x=-11/2
x₁=5 1/2 ∨ x₂=-5 1/2