Cześć ;-)
c)
[tex]4^2\cdot(\frac{1}{4})^2-(\frac{1}{5})^3\cdot5^3=\\\\=(4\cdot\frac{1}{4})^2-(\frac{1}{5}\cdot5)^3=1^2-1^3=1-1=\boxed0[/tex]
d)
[tex](\frac{3}{7})^3:(-\frac{6}{7})^3-15^4:(-5)^4=\\\\=(\frac{3}{7}:(-\frac{6}{7}))^3-15^4:5^4=\\\\=(\frac{3}{7}\cdot(-\frac{7}{6})^3-(15:5)^4=(-\frac{1}{2})^3-3^4=\\\\=-\frac{1}{8}-81=-81\frac{1}{8}=-81\frac{125}{1000}=\boxed{-81,125}[/tex]
Pozdrawiam!
