Odpowiedź:
Szczegółowe wyjaśnienie:
Zad 6
[tex]a)\ (\frac{1}{7})^2*14^2-10^5*(\frac{1}{5})^5=(\frac{1}{7}*14)^2-(10*\frac{1}{5})^5=2^2-2^5=4-32=-28\\b)\ 35^2:(-7)^2+(-6)^3:(-2)^3=(35:(-7))^2+(-6:(-2))^3=(-5)^2+3^3=25+27=52\\c)\ 4^2*(\frac{1}{4})^2-(\frac{1}{5})^3*5^3=(4*\frac{1}{4})^2-(\frac{1}{5}*5)^3=1^2-1^3=0\\d)\ (\frac{3}{7})^3:(-\frac{6}{7})^3-15^4:(-5)^4=(\frac{3}{7}*(-\frac{7}{6}))^3-(15:(-5))^4=(-\frac{1}{2})^3-(-3)^4=-\frac{1}{8}-81=-81\frac{1}{8}[/tex]
Zad 7
[tex]a)\ (\frac{1}{42})^3:(-\frac{1}{21})^3-100^3*(-\frac{1}{10})^3=(\frac{1}{42}*(-21))^3-(100*(-\frac{1}{10}))^3=(-\frac{1}{2})^3-(-10)^3=-\frac{1}{8}-1000=-1000\frac{1}{8}\\b) \ (1,2)^3:12^3-(0,6)^5*(-1\frac{2}{3})^5=(\frac{12}{10}*\frac{1}{12})^3-(\frac{6}{10}*(-\frac{5}{3}))^5=(\frac{1}{10})^3-(-1)^5=\frac{1}{1000}+1=1\frac{1}{1000}\\c)\ -(-27)^3*(-\frac{1}{9})^3-12^3:(-3)^3=-(-27:(-\frac{1}{9}))^3-(12:(-3))^3=-3^3-(-4)^3=-27+64=37\\[/tex]
[tex]d)\ (-2\frac{2}{3})^{15}*(0,375)^{15}+(-\frac{2}{3})^2*(0,75)^2=(-\frac{8}{3}*\frac{3}{8})^{15}+(-\frac{2}{3}*\frac{3}{4})^2=(-1)^{15}+(-\frac{1}{2})^2=-1+\frac{1}{4}=-\frac{3}{4}[/tex]
