1.
[tex]a) \ 2\frac{1}{3}+6\frac{2}{3} = 8\frac{3}{3} = 9\\\\\\b) \ 6\frac{3}{5}-8\frac{4}{5} = -2\frac{1}{5}\\\\\\c) \ 1\frac{1}{2}+\frac{1}{3} = 1\frac{3}{6}+\frac{2}{6} = 1\frac{5}{6}\\\\\\d) \ 5\frac{2}{3}+\frac{1}{2} = 5\frac{4}{6}+\frac{3}{6} = 5\frac{7}{6} = 6\frac{1}{6}\\\\\\e) \ 2\frac{3}{4}-4\frac{1}{2} = 2\frac{3}{4}-4\frac{2}{4} = 2\frac{3}{4}-3\frac{6}{4} = -1\frac{3}{4}\\\\\\f) \ 5\frac{1}{4}-4\frac{2}{3} = 5\frac{3}{12}-4\frac{8}{12} = 4\frac{15}{12} -4\frac{8}{12} = \frac{7}{12}[/tex]
[tex]g) \ (\frac{2}{3}\cdot\frac{4}{9}):\frac{1}{6} =\frac{8}{27}\cdot\frac{6}{1} = \frac{8}{9}\cdot2 = \frac{16}{9} = 1\frac{8}{9}\\\\\\h) \ (\frac{5}{8}\cdot\frac{15}{4}):\frac{6}{5} = \frac{75}{32}\cdot\frac{5}{6} =\frac{25}{32}\cdot\frac{5}{3} = \frac{125}{64} = 1\frac{61}{64}\\\\\\i) \ (\frac{1}{2}\cdot\frac{1}{3}):\frac{1}{6} = \frac{1}{6}\cdot6 = 1[/tex]
[tex]j) \ (\frac{2}{3}\cdot\frac{5}{6}):\frac{8}{15} = \frac{10}{18}\cdot\frac{15}{8} = \frac {5}{6}\cdot\frac{5}{4} =\frac{25}{24} = 1\frac{1}{24}\\\\\\k) \ (1\frac{2}{3}:8\frac{4}{7})\cdot\frac{6}{7} = (\frac{5}{3}:\frac{60}{7})\cdot\frac{6}{7} = \frac{5}{3}\cdot\frac{7}{60})\cdot\frac{6}{7} = \frac{35}{180}\cdot\frac{6}{7} = \frac{5}{30} = \frac{1}{6}[/tex]
[tex]l) \ (2\frac{6}{7}:1\frac{3}{7})\cdot\frac{1}{2} = (\frac{20}{7}:\frac{10}{7})\cdot\frac{1}{2} = (\frac{20}{7}\cdot\frac{7}{10})\cdot\frac{1}{2} = 2\cdot\frac{1}{2} = 1[/tex]
