[tex]dane:\\t =0,5 \ h = 0,5\cdot3600 \ s = 1800 \ s\\\Delta v = 2\frac{km}{min} = \frac{2000 \ m}{60 \s}=\frac{100}{3}\frac{m}{s} = 33,(3)\frac{m}{s} \\F = 2 \ 000 \ N\approx33,3\frac{m}{s}\\szukane:\\m = ?\\\\Rozwiazanie\\\\Z \ III \ zasady \ dynamiki\\\\a = \frac{F}{m} \ \ \rightarrow \ \ m = \frac{F}{a}\\\\ale: \ \ a = \frac{\Delta v}{t}=\frac{\frac{100}{3}\frac{m}{s}}{1800 \s} =0,0185\frac{m}{s^{2}}[/tex]
[tex]m = \frac{2000 \ N}{0,0185\frac{m}{s^{2}}} = \frac{2000 \ kg\cdot\frac{m}{s^{2}}}{0,0185\frac{m}{s^{2}}}\\\\\underline{m \approx 108 \ 108,1 \ kg}[/tex]
