[tex]a = \frac{7}{10} \ dm\\\\h = 1\frac{2}{3} \ dm = \frac{1\cdot3+2}{3} \ dm = \frac{5}{3} \ dm\\\\P = ?\\\\\\P = a\times h\\\\P = \frac{7}{10} \ dm\times \frac{5}{3} \ dm=\frac{7}{2} \ dm\times\frac{1}{3} \ dm\\\\\underline{P = \frac{7}{6} \ dm^{2} = 1\frac{1}{6} \ dm^{2}}[/tex]
Odp. Pole równoległoboku P = 1¹/₆ dm².
