Cześć ;-)
Od a) do c)
[tex]\frac{13-1}{2+4}=\frac{12}{6}=\boxed2\\\\\frac{1,2-0,9}{0,7+0,8}=\frac{0,3}{1,5}=\frac{3}{15}=\frac{1}{5}=\frac{2}{10}=\boxed{0,2}\\\\\frac{7,1-0,8}{5\cdot0,6}=\frac{6,3}{3}=\boxed{2,1}[/tex]
Od d) do f)
[tex]\frac{6,53-6,32}{2,3-1,6}=\frac{0,21}{0,7}=\boxed{0,3}\\\\2\cdot\frac{5}{1,6+0,9}=2\cdot\frac{5}{2,5}=2\cdot2=\boxed4\\\\\frac{0,6\cdot7}{0,2}\cdot\frac{1}{2,2+0,8}=\frac{4,2}{0,2}\cdot\frac{1}{3}=21\cdot\frac{1}{3}=\frac{21}{3}=\boxed7[/tex]
Pozdrawiam!
