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[tex]a)\ \ -2\frac{1}{3}\cdot(-\frac{27}{28})=\frac{\not7^1}{\not3_{1}}\cdot\frac{\not27^9}{\not28_{4}}=\frac{9}{4}=2\frac{1}{4}\\\\\\b)\ \ -3\frac{3}{8}:5\frac{1}{16}=-\frac{27}{8}:\frac{81}{16}=-\frac{\not27^1}{\not8_{1}}\cdot\frac{\not16^2}{\not81_{3}}=-\frac{2}{3}\\\\\\c)\ \ -1\frac{1}{7}\cdot1\frac{11}{24}:\frac{3}{5}=-\frac{\not8^1}{\not7_{1}}\cdot\frac{\not35^5}{\not24_{3}}:\frac{3}{5}=-\frac{5}{3}\cdot\frac{5}{3}=-\frac{25}{9}=-2\frac{7}{9}[/tex]

[tex]d)\ \ 3\frac{1}{2}-3\frac{1}{6}:(-2\frac{1}{9})=3\frac{1}{2}+\frac{19}{6}:\frac{19}{9}=3\frac{1}{2}+\frac{\not19^1}{\not6_{2}}\cdot\frac{\not9^3}{\not19_{1}}=3\frac{1}{2}+\frac{3}{2}=3\frac{1}{2}+1\frac{1}{2}=4\frac{2}{2}=5[/tex]

GF21 GF21 · Answer 2 · 2021-09-15T18:41:39+02:00

Odpowiedź:

a) [tex]-2\frac{1}{3} *(-\frac{27}{28})=-\frac{7}{3} *(-\frac{27}{28})=\frac{7}{3} *\frac{27}{28}=\frac{9}{4} =2\frac{1}{4}[/tex]

b)[tex]-3\frac{3}{8} : 5\frac{1}{16} =-\frac{27}{8} :\frac{81}{16} =-\frac{27}{8} *\frac{16}{81}=-\frac{1}{8} *\frac{16}{3}=-\frac{1}{1} *\frac{2}{3}=-1 *\frac{2}{3}=-\frac{2}{3}[/tex]

c)

[tex]-1\frac{1}{7} *1\frac{11}{24} :\frac{3}{5} =-1\frac{1}{7} *1\frac{11}{24} *\frac{5}{3}=-\frac{8}{7} *\frac{35}{24} *\frac{5}{3}=-\frac{1}{7} *\frac{35}{3} *\frac{5}{3}=\\ \\ =-\frac{1}{7} *\frac{35}{3} *\frac{5}{3}=-\frac{1}{1} *\frac{5}{3} *\frac{5}{3}=-1*\frac{25}{9} =-2\frac{7}{9}[/tex]

d)

[tex]3\frac{1}{2} -3\frac{1}{6} :(-2\frac{1}{9} )=3\frac{1}{2} -\frac{19}{6} :(-\frac{19}{9} )=3\frac{1}{2} -\frac{19}{6} *(-\frac{9}{19})=3\frac{1}{2} -\frac{1}{6} *(-\frac{9}{1})=\\ \\ =3\frac{1}{2} +\frac{1}{6} *\frac{9}{1}=3\frac{1}{2} +\frac{1}{2} *\frac{3}{1}=3\frac{1}{2} +\frac{3}{2}=\frac{7}{2} +\frac{3}{2}=\frac{10}{2} =5[/tex]

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