Witaj :)
[tex]i)\ \sqrt{7+\sqrt[3]{8} }=\sqrt{7+2} =\sqrt{9}=3\\\\h)\ \sqrt[3]{108}\cdot \sqrt{4} =\sqrt[3]{27\cdot4} \cdot 2=\sqrt[3]{27}\cdot \sqrt[3]{4}\cdot 2=3\cdot \sqrt[3]{4}\cdot 2=6\sqrt[3]{4} \\\\k)\ \sqrt[3]{19} \cdot \sqrt{64} =8\sqrt[3]{19} \\\\j)\ \sqrt{20}-\sqrt[3]{64}=\sqrt{4\cdot 5} -4=\sqrt{4}\cdot \sqrt{5}-4=2\sqrt{5}-4=2(\sqrt{5}-2)\\\\l)\ \sqrt[3]{36}-\sqrt{81} =\sqrt[3]{36} -9[/tex]
