Odpowiedź:
[tex] \frac{3}{8} x + 2 \frac{1}{4 } = - 5 \frac{1}{2} \div ( - \frac{2}{3} - 1 \frac{1}{3} )[/tex]
[tex] \frac{3}{8} x + 2 \frac{1}{4} = - 5 \frac{1}{2} \div ( - 2)[/tex]
[tex] \frac{3}{8} x + 2 \frac{1}{4} = - \frac{11}{2} \times ( - \frac{1}{2} )[/tex]
[tex] \frac{3}{8} x + 2 \frac{1}{4} = \frac{11}{4} [/tex]
[tex] \frac{3}{8} x = \frac{11}{4} - \frac{9}{4} [/tex]
[tex] \frac{3}{8} x = \frac{1}{2} [/tex]
[tex]x = \frac{1}{2} \times \frac{8}{3} [/tex]
[tex]x = \frac{4}{3} [/tex]