PROSZE O POMOC TE 2 ZADANIA PILNE
DAM NAJ <33

Odpowiedź:
1.
[tex] \sqrt{252} = 6 \sqrt{7} [/tex]
[tex] \sqrt{242} = 11 \sqrt{2} [/tex]
2.
[tex] \sqrt[3]{2} \times \sqrt[3]{3} \times \sqrt[3]{36} = \sqrt[3]{2 \times 3 \times 36} = \sqrt[3]{216} = 6[/tex]