Cześć ;-)
Od a) do d)
[tex]\frac{2}{3}+\frac{1}{4}=\frac{8}{12}+\frac{3}{12}=\frac{11}{12}\\\\\frac{5}{9}+\frac{3}{5}=\frac{25}{45}+\frac{27}{45}=\frac{52}{45}=1\frac{7}{45}\\\\\frac{2}{3}+\frac{4}{5}=\frac{10}{15}+\frac{12}{15}=\frac{22}{15}=1\frac{7}{15}\\\\\frac{5}{8}+\frac{3}{7}=\frac{35}{56}+\frac{24}{56}=\frac{59}{56}=1\frac{3}{56}[/tex]
Od e) do h)
[tex]1\frac{1}{2}+\frac{3}{8}=1\frac{4}{8}+\frac{3}{8}=1\frac{7}{8}\\\\\frac{2}{9}+1\frac{7}{27}=\frac{6}{27}+1\frac{7}{27}=1\frac{13}{27}\\\\1\frac{5}{6}+3\frac{1}{9}=1\frac{15}{18}+3\frac{2}{18}=4\frac{17}{18}\\\\2\frac{1}{10}+1\frac{7}{15}=2\frac{3}{30}+1\frac{14}{30}=3\frac{17}{30}[/tex]
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