Cześć ;-)
Obliczenia
[tex]-\frac{1}{\not2_1}\cdot\frac{\not4^2}{5}\cdot(-1,5)=-\frac{2}{5}\cdot(-1\frac{1}{2})=-\frac{\not2^1}{5}\cdot(-\frac{3}{\not2_1})=\frac{3}{5}\\\\-2,1\cdot(-\frac{\not2^1}{7})\cdot\frac{5}{\not6_3}=-2\frac{1}{10}\cdot(-\frac{5}{21})=-\frac{\not21_1}{\not10_2}\cdot(-\frac{\not5^1}{\not21_1})=\frac{1}{2}\\\\-\frac{2}{3}\cdot(-1,5)\cdot(-3,6)=-\frac{2}{3}\cdot(-1\frac{1}{2})\cdot(-3\frac{3}{5})=-\frac{\not2^1}{\not3_1}\cdot(-\frac{\not3^1}{\not2_1})\cdot(-3\frac{3}{5})=-3\frac{3}{5}[/tex]
Pozdrawiam!
