14.
[tex]a) \ b - \frac{10b-5}{5} = b-2b+1 = 1 - b\\\\\\b) \ \frac{8x-4}{4}-\frac{x}{2} =2x-1-\frac{x}{2} = 1\frac{1}{2}x -1\\\\\\c) \ 2(n-3)-\frac{4n+1}{2} =2n-6-2n-\frac{1}{2} = -6\frac{1}{2}[/tex]
[tex]d) \ \frac{3a-4}{5}-2(6-5a) = \frac{3}{5}a - \frac{4}{5}-12+10a = 10\frac{3}{5}a -12\frac{4}{5}[/tex]
[tex]e) \ x - \frac{x-1}{3}+3(x-\frac{1}{9}) =x - \frac{1}{3}x + \frac{1}{3}+3x-\frac{1}{3} = 4x-\frac{1}{3}x = 3\frac{2}{3}x[/tex]
[tex]f) \ \frac{2p+5}{6}+\frac{3-4p}{3} =\frac{1}{3}p+\frac{5}{6}+1-\frac{4}{3}p = 1\frac{5}{6}-p[/tex]
[tex]g) \ \frac{x+3}{2}-\frac{4x+2}{4}+\frac{x}{3} =\frac{6(x+3)-3(4x+2)+4x}{12} = \frac{6x+8-12x-6+4x}{12} = \frac{12-2x}{12} = 1-\frac{1}{6}x[/tex]
[tex]h) \ 2m+\frac{3m-1}{5}-\frac{2m-3}{15}=2m + \frac{3(3m-1)-2m+3}{15} =2m+\frac{9m-3-2m+3}{15} =\\\\=2m+\frac{7m}{15} = 2\frac{7}{15}m[/tex]
[tex]i) \ \frac{2k-7}{3} - \frac{4+10k}{6} + \frac{k}{5}=\frac{10(2k-7)-5(4+10k)+6k}{30}=\frac{20k-70-20-50k+6k}{30} =\\\\= \frac{-90-24k}{30} =-3-\frac{8}{10}k[/tex]
