była bym wdzięczna o pomoc w tych zadaniach ​



Była Bym Wdzięczna O Pomoc W Tych Zadaniach class=

Odpowiedź :

Odpowiedź:

a)

[tex]234 - 50 + 266 - 450 = 234 + 266 - 50 - 450 = 500 - 500 = 0[/tex]

b)

[tex] {11}^{2} - (5 + 4)^{2} \div {3}^{4} = 121 - {9}^{2} \div 81 = 121 - 81 \div 81 = 121 - 1 = 120[/tex]

c)

[tex]3(5 - 3)^{3} - 5 \times {2}^{4} \div {4}^{2} = 3 \times {2}^{3} - 5 \times 16 \div 16 = 3 \times 8 - 5 \times 1 = 24 - 5 = 19[/tex]

d)

[tex]3 \times (5 - (1 + 2) ^{3} \div 9) ^{4} = 3 \times (5 - {3}^{3} \div 9) ^{4} = 3 \times (5 - 27 \div 9) ^{4} = 3 \times (5 - 3) ^{4} = 3 \times 2 ^{4} = 3 \times 16 = 48[/tex]

e)

[tex](458 - ( {12}^{2} + {4}^{3} )) \div {5}^{2} = (458 - (144 + 64)) \div 25 = (458 - 208) \div 25 = 250 \div 25 = 10[/tex]

f)

[tex] {5}^{3} - {12}^{2} \div {2}^{4} \div {3}^{2} = 125 - 144 \div 16 \div 9 = 125 - 9 \div 9 = 125 - 1 = 124[/tex]

g)

[tex]( {2}^{10} \div {4}^{3} ) \div ( {5}^{2} - {3}^{2} ) ^{1} =( 1024 \div 64) \div (25 - 9) = 16 \div 16 = 1[/tex]

h)

[tex]((2 + 5) ^{2} - (2 + 4) \times {2}^{3} ) ^{10} = ( {7}^{2} - 6 \times 8) ^{10} = (49 - 48) ^{10} = {1}^{10} = 1[/tex]