Cześć ;-)
b)
[tex]\frac{2\frac{1}{4}:(3\frac{2}{3}-1\frac{1}{4})}{1\frac{25}{29}}=\frac{\frac{9}{4}:(3\frac{8}{12}-1\frac{3}{12})}{\frac{54}{29}}=\frac{\frac{9}{4}:2\frac{5}{12}}{\frac{54}{29}}=\\\\=\frac{\frac{9}{4}:\frac{29}{12}}{\frac{54}{29}}=\frac{\frac{9}{4}\cdot\frac{12}{29}}{\frac{54}{29}}=\frac{\frac{27}{29}}{\frac{54}{29}}=\frac{27}{29}\cdot\frac{29}{54}=\frac{1}{2}[/tex]
c)
[tex]\frac{2\frac{2}{3}}{(1\frac{1}{4}-\frac{5}{6})\cdot1\frac{1}{5}}=\frac{\frac{8}{3}}{(1\frac{3}{12}-\frac{10}{12})\cdot\frac{6}{5}}=\frac{\frac{8}{3}}{(\frac{15}{12}-\frac{10}{12})\cdot\frac{6}{5}}=\\\\=\frac{\frac{8}{3}}{\frac{5}{12}\cdot\frac{6}{5}}=\frac{\frac{8}{3}}{\frac{1}{2}}=\frac{8}{3}\cdot2=\frac{16}{3}=5\frac{1}{3}[/tex]
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