Odpowiedź:
I. - C
II. - B
III. - D
IV. - A
Szczegółowe wyjaśnienie:
I. zostawiamy bez zmian
II. [tex]\frac{2}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } = \frac{2\sqrt{3} }{3} \\[/tex]
III. [tex]\frac{3}{\sqrt{6} } *\frac{\sqrt{6} }{\sqrt{6} } = \frac{3\sqrt{6} }{6} = \frac{\sqrt{6} }{2}[/tex]
IV. [tex]\frac{6}{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2} } = \frac{6\sqrt{2} }{2} = 3\sqrt{2}[/tex]
A [tex]\sqrt{18} = \sqrt{3^{2} *2} = 3\sqrt{2}[/tex]
B. [tex]\sqrt{\frac{4}{3} } = \frac{\sqrt{4} }{\sqrt{3} } = \frac{2}{\sqrt{3} } * \frac{\sqrt{3} }{\sqrt{3} } = \frac{2\sqrt{3} }{3}[/tex]
C. [tex]\sqrt{12} = \sqrt{2^{2}*3 } = 2\sqrt{3}[/tex]
D. [tex]\sqrt{\frac{3}{2} } = \frac{\sqrt{3} }{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2} } = \frac{\sqrt{3*2} }{2} = \frac{\sqrt{6} }{2}[/tex]
