[tex]dane:\\|XY| = s_1 = 20 \ km = 20 \ 000 \ m\\v_1 = 5\frac{m}{s}\\v_2 = 20\frac{m}{s}\\szukane:\\s_2 = ?\\\\Rozwiazanie\\\\t_1 =\frac{s}{v_1}\\oraz\\t_2 = \frac{s_2}{v_2}\\\\t_1 = t_2\\\\\frac{s_1}{v_1}=\frac{s_2}{v_2}\\\\s_2\cdot v_1 = s_1\cdot v_2 \ \ /:v_1\\\\s_2 = s_1\cdot\frac{v_2}{v_1}\\\\s_2 = 20 000 \ m\cdot\frac{20\frac{m}{s}}{5\frac{m}{s}}\\\\s_2 = 20 \ 000 \ m\cdot4\\\\\underline{s_2 = 80 \ 000 \ m = 80 \ km}[/tex]
Odp. Drugi samochód pokonał odległość s₂ = 80 km.
