[tex]2\log5-1=\log5^2-\log10=\log\dfrac{25}{10}=\log\dfrac{5}{2}[/tex]
[tex]0,5(1+3\log_32)=0,5(\log_33+\log_32^3)=0,5(\log(3\cdot8))=\log24^{0,5}=\\=\log\sqrt{24}=\log2\sqrt6[/tex]