Odpowiedź:
a)[tex]\frac{1}{3} \sqrt{6} +1\frac{2}{3} \sqrt{6} =2\sqrt{6}[/tex]
b)[tex]\sqrt{7} -3\frac{2}{3}\sqrt{7} } =-2\frac{2}{3} \sqrt{7}[/tex]
c)[tex]3\sqrt{11} -\frac{\sqrt{11} }{3}=2\frac{2}{3} \sqrt{11}[/tex]
d)[tex]\frac{\sqrt{2} }{5} +\frac{\sqrt{2} }{10} =\frac{2\sqrt{2} }{10} +\frac{\sqrt{2} }{10} =\frac{3\sqrt{2} }{10}[/tex]
e)[tex]-6\sqrt{3}*\frac{1}{2} =-3\sqrt{3}[/tex]
f)[tex]5\sqrt{13} *(-0,4)=5*(-0,4)\sqrt{13} =-2\sqrt{13}[/tex]
g)0,1√2*√2=0,1*2=0,2
h)[tex]1,2\sqrt{10} *2\sqrt{10}=1,2*2*\sqrt{10}*\sqrt{10} =2,4*10=24[/tex]
Szczegółowe wyjaśnienie:
